∆ ABC is isosceles with AB = AC = 7.5 cm, and BC = 9 cm (in

∆ ABC is isosceles with AB = AC = 7.5 cm, and BC = 9 cm (in Figure). The height AD from A to BC, is 6 cm. Find the area of ∆ ABC. What will be the height from C to AB i.e., CE?

triangle ABC is isosceles with AB AC 7.5 cm

NCERT Solutions for Class 7 Maths Chapter 11 Perimeter and Area

∆ ABC is isosceles with AB = AC = 7.5 cm, and BC = 9 cm (in

NCERT Solutions for Class 7 Maths Chapter 11 Perimeter and Area

NCERT Solutions for Class 7 Maths Chapter 11 Perimeter and Area Ex

∆ ABC is isosceles with AB = AC = 7.5 cm, and BC = 9 cm (in

Triangle ABC is isosceles with AB=BC=12 cm. Side AC is extended to

ΔABC is isosceles with AB=AC=7cm and BC=9cm. The height AD from A

Ex 9.1, 8 - ABC is isosceles with AB = AC = 7.5 cm and BC = 9 cm